[buug] regex question
Aaron T Porter
atporter at primate.net
Wed Apr 30 14:37:51 PDT 2003
On Wed, Apr 30, 2003 at 01:56:24PM -0700, Nick Moffitt wrote:
> > ($id) = $_ =~ m"UserID=(.*)&";
>
> That's nice, but it does a lot of backtracking from the end to
> figure out which & is the terminating symbol. It's much more
> efficient to use some variant of "[^&]+" instead of ".*". The match
> then stops at the first & it sees instead of hoping for a later one in
> the string.
My perl code is rarely (if ever) described as efficient :)
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